ADDENDUM 08/16/03: I knew my "textbook" explanation of this was too simplistic. However, I'm guilty of that most dreaded of all scientific/education guffaws; saying or hearing something so many times that you just accept it without even thinking! Coises, foiled again! Professor A. John Mallinckrodt of Cal Poly Pomona provided a much better physics explanation. In his own words copied from his email:
Looking at the torque due to gravity around the supported end and
setting it equal to the rotational inertia about the supported end
times the angular acceleration, you find Thanks, John!
so
alpha = (3/2)*(g/L)
Therefore, the initial acceleration of the CM is
a_cm = alpha*(L/2) = (3/4)*g
and the initial acceleration of the free end is
a_free = alpha*L = (3/2)*g